(5/X+7)-(2/x-7)=(10x/x^2-49)

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Solution for (5/X+7)-(2/x-7)=(10x/x^2-49) equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

5/X-(2/x)+7+7 = (10*x)/(x^2)-49 // - (10*x)/(x^2)-49

5/X-(2/x)-((10*x)/(x^2))+7+7+49 = 0

5/X-2*x^-1-10*x^-1+7+7+49 = 0

-12*x^-1 = -(5*X^-1+63) // : -12

x^-1 = (5*X^-1+63)/12

-1 < 0

1/(x^1) = (5*X^-1+63)/12 // * x^1

1 = x^1*((5*X^-1+63)/12) // : (5*X^-1+63)/12

12*(5*X^-1+63)^-1 = x^1

x = 12*(5*X^-1+63)^-1

x = 12*(5*X^-1+63)^-1

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